Match List-I with List-II:List-IList-IIA. Coe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Coefficient of Viscosity $(\eta)$: From $F = \eta A \frac{dv}{dy}$,we have $\eta = \frac{F}{A(dv/dy)}$. Dimensions: $\frac{[M L T^{-2}]}{[L^2

Vedclass · Accepted Answer

$A-III, B-IV, C-II, D-I$

Vedclass · Answer

(C) $1$. Coefficient of Viscosity $(\eta)$: From $F = \eta A \frac{dv}{dy}$,we have $\eta = \frac{F}{A(dv/dy)}$. Dimensions: $\frac{[M L T^{-2}]}{[L^2][T^{-1}]} = [M L^{-1} T^{-1}]$. (Matches $III$)$2$. Surface Tension $(S)$: $S = \frac{F}{l}$. Dimensions: $\frac{[M L T^{-2}]}{[L]} = [M L^0 T^{-2}]$. (Matches $IV$)$3$. Angular momentum $(L)$: $L = mvr$. Dimensions: $[M][L T^{-1}][L] = [M L^2 T^{-1}]$. (Matches $II$)$4$. Rotational Kinetic energy $(K)$: $K = \frac{1}{2} I \omega^2$. Dimensions: $[M L^2][T^{-1}]^2 = [M L^2 T^{-2}]$. (Matches $I$)Thus,the correct matching is $A-III, B-IV, C-II, D-I$.

List-$I$	List-$II$
$A$. Coefficient of Viscosity	$I$. $[M L^2 T^{-2}]$
$B$. Surface Tension	$II$. $[M L^2 T^{-1}]$
$C$. Angular momentum	$III$. $[M L^{-1} T^{-1}]$
$D$. Rotational Kinetic energy	$IV$. $[M L^0 T^{-2}]$

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Coefficient of Viscosity $I$. $[M L^2 T^{-2}]$
$B$. Surface Tension $II$. $[M L^2 T^{-1}]$
$C$. Angular momentum $III$. $[M L^{-1} T^{-1}]$
$D$. Rotational Kinetic energy $IV$. $[M L^0 T^{-2}]$

Similar Questions

Which of the following statements is true?

Identify the incorrect statement.

Which of the following pairs does not have the same dimensions?

Which relation is wrong?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match List-$I$ with List-$II$:List-$I$List-$II$$A$. Coefficient of Viscosity$I$. $[M L^2 T^{-2}]$$B$. Surface Tension$II$. $[M L^2 T^{-1}]$$C$. Angular momentum$III$. $[M L^{-1} T^{-1}]$$D$. Rotational Kinetic energy$IV$. $[M L^0 T^{-2}]$